microbiology an introduction 13th edition test bank

Correct Answer: D

Rationale: The correct answer is D because antibody diversity is generated by rearrangements of DNA encoding variable regions of heavy and light chains (choice A) and by the combination of different heavy and light chains that form the antigen binding site (choice B). Step 1: DNA rearrangements create different variable regions in heavy and light chains. Step 2: Combination of different heavy and light chains leads to unique antigen binding sites. Step 3: This diversity allows antibodies to bind to different epitopes on the same antigen. Step 4: Choice C is incorrect as antibodies do not physically change shape to bind different epitopes.

Correct Answer: A

Rationale: The correct answer is A: Lipopolysaccharides. Endotoxins are a type of bacterial toxin found in the outer membrane of Gram-negative bacteria. They consist of lipid A, which is a lipid component, and polysaccharides, making them lipopolysaccharides. Lipoproteins (choice B) and glycoproteins (choice C) do not accurately describe the chemical structure of endotoxins. "None of the above" (choice D) is incorrect as lipopolysaccharides are indeed the chemical structure of endotoxins.

Correct Answer: D

Rationale: The correct answer is D: Thin mobile bacillus with central spore. This is because the causative agent of botulism, Clostridium botulinum, is a gram-positive bacillus that typically appears as a thin rod-shaped bacterium with a central endospore. This characteristic morphology is essential in the identification of Clostridium botulinum. A: Gram-positive bacillus with subterminal spore - This is incorrect as Clostridium botulinum typically has a central endospore, not a subterminal one. B: Thick gram-positive non-spore-forming bacillus - This is incorrect as Clostridium botulinum forms endospores, although they are not thick. C: Gram-positive bacillus with terminal spore - This is incorrect as the spore of Clostridium botulinum is typically central, not terminal.

Correct Answer: A

Rationale: The correct answer is A: Streptococcus pyogenes. Rationale: 1. Gram-positive cocci in chains: S. pyogenes is a Gram-positive cocci in chains. 2. Catalase-negative: S. pyogenes is catalase-negative. 3. Beta-hemolytic: S. pyogenes exhibits beta-hemolysis. Summary of other choices: B: Streptococcus pneumoniae is alpha-hemolytic and optochin-sensitive. C: Enterococcus faecalis is catalase-negative, but not typically beta-hemolytic. D: Staphylococcus aureus is catalase-positive and coagulase-positive.

Correct Answer: C

Rationale: The correct answer is C: peritrichous. Peritrichous bacteria have flagella distributed all over the cell surface, providing motility in various directions. This allows them to move efficiently through their environment. Option A and D, lophotrichous, have flagella clustered at one or both ends of the cell, limiting movement to specific directions. Option B, amphitrichous, have flagella at both ends of the cell, also limiting movement compared to peritrichous bacteria. Therefore, peritrichous is the correct choice for bacteria with flagella distributed over the general cell surface.