microbiology chapter 10 test bank

Correct Answer: B

Rationale: The correct answer is B: Family Reoviridae. Reassortment of gene segments occurs in segmented viruses like Reoviruses. In Reoviridae, each segment encodes a specific protein, allowing for reassortment to generate new strains. Togaviridae (A) is a non-segmented virus, not capable of reassortment. Picornaviridae (C) and Paramyxoviruses (D) are also non-segmented viruses, limiting their ability for reassortment. Therefore, the correct choice is B due to the segmented nature of Reoviruses allowing for genetic reassortment.

Correct Answer: D

Rationale: The correct answer is D: scanning electron microscope. A scanning electron microscope provides a three-dimensional image of a specimen by scanning a focused electron beam across the surface of the specimen, detecting the electrons that are emitted from the surface, and creating a detailed image. This is achieved through the detection of secondary electrons, backscattered electrons, and X-rays emitted from the specimen surface. A dark-field microscope (choice A) utilizes oblique lighting to enhance contrast and is not specifically designed to provide a 3D image. A transmission electron microscope (choice B) uses a beam of electrons transmitted through a specimen to create a 2D image at high magnification. A bright-field microscope (choice C) is a basic microscope that illuminates a specimen with uniform light and does not provide a 3D image like a scanning electron microscope does.

Correct Answer: C

Rationale: The correct answer is C: Granuloma formation. In response to tuberculosis antigen (tuberculin), the immune system forms a granuloma at the injection site as a defense mechanism. Granulomas are organized collections of immune cells that wall off the antigen and prevent its spread. This process involves macrophages, T cells, and fibroblasts. Choice A (Cells cytotoxity) is incorrect because tuberculin test does not involve direct cell cytotoxicity. Choice B (Reagin type cytotoxity) is incorrect as reagin type hypersensitivity is associated with allergic reactions, not granuloma formation. Choice D (Immunocomplex cytotoxity) is also incorrect as immunocomplex cytotoxicity refers to tissue damage caused by immune complexes, not granuloma formation.

Correct Answer: A

Rationale: The correct answer is A: Neutralization reaction. This is the most appropriate serological test to reveal botulinum toxin because it involves mixing the patient's serum with known botulinum antitoxin. If the patient's serum contains botulinum toxin, it will neutralize the antitoxin, leading to a lack of toxin-neutralizing ability. The other choices are incorrect because agglutination reaction involves clumping of cells, not suitable for detecting botulinum toxin; Bordet-Gengou test is used to detect antibodies in pertussis infection, not botulinum toxin; and precipitation reaction involves the formation of a solid when two solutions are mixed, not ideal for detecting botulinum toxin.

Correct Answer: B

Rationale: The correct answer is B: Gamma globulin, as it is not a primary immunodeficiency disease. Primary immunodeficiency diseases are genetic disorders that affect the immune system's ability to fight infections. A: Glanzmann-Riniker hypergammaglobulinemia is a rare primary immunodeficiency characterized by elevated levels of gammaglobulins. C: Variable hypogammaglobulinemia is a primary immunodeficiency disease where there are fluctuating levels of gammaglobulins. D: Bruton hypogammaglobulinemia, also known as X-linked agammaglobulinemia, is a primary immunodeficiency characterized by a lack of B cells and gammaglobulins. In summary, B is the correct answer as gamma globulin is not a primary immunodeficiency disease, whereas A, C, and D are all examples of primary immunodeficiency diseases affecting gammaglobulins levels.