microbiology an introduction 13th edition test bank

Correct Answer: A

Rationale: The correct answer is A: Staphylococcus epidermidis. Step 1: Gram-positive cocci in clusters suggest staphylococci. Step 2: Catalase-positive and coagulase-negative narrows it down to Staphylococcus epidermidis, as it is catalase-positive and coagulase-negative. Staphylococcus aureus (B) is catalase-positive and coagulase-positive. Streptococcus pyogenes (C) is catalase-negative. Enterococcus faecalis (D) is catalase-negative and coagulase-negative.

Correct Answer: A

Rationale: The correct answer is A: Acid resistance. Tuberculosis mycobacteria have a unique cell wall structure that makes them resistant to acid-fast staining methods like Ziehl-Neelsen. This is due to the high lipid content of their cell walls, specifically mycolic acids, which prevent the penetration of stains and acids. The red bacilli observed in the smear indicate that the mycobacteria retained the primary stain (carbolfuchsin) after acid-alcohol decolorization, confirming their acid resistance. Summary: - Choice A: Acid resistance is correct due to the unique cell wall structure of tuberculosis mycobacteria. - Choice B: Alkali resistance is incorrect as mycobacteria are not known for being resistant to alkalis. - Choice C: Alcohol resistance is incorrect as mycobacteria are not specifically resistant to alcohols. - Choice D: Encapsulation is incorrect as mycobacteria are not encapsulated bacteria.

Correct Answer: D

Rationale: The correct answer is D because antibody diversity is generated by rearrangements of DNA encoding variable regions of heavy and light chains (choice A) and by the combination of different heavy and light chains that form the antigen binding site (choice B). Step 1: DNA rearrangements create different variable regions in heavy and light chains. Step 2: Combination of different heavy and light chains leads to unique antigen binding sites. Step 3: This diversity allows antibodies to bind to different epitopes on the same antigen. Step 4: Choice C is incorrect as antibodies do not physically change shape to bind different epitopes.

Correct Answer: D

Rationale: The correct answer is D: Mycoplasma. Mycoplasma is the only bacteria among the choices that have sterols in their cytoplasmic membrane. This feature helps stabilize their membrane structure due to the lack of a cell wall. Legionella (A), Bacillus (B), and Rickettsia (C) do not contain sterols in their cytoplasmic membrane. Legionella has a unique lipid composition, Bacillus has peptidoglycan in its cell wall, and Rickettsia is an intracellular parasite lacking sterols in its membrane.

Correct Answer: C

Rationale: Rationale: 1. The male reproductive system is considered sterile as it does not have a natural microbiota. 2. Any presence of microorganisms in this system could indicate an infection or disease. 3. Therefore, choice C, sterile with no normal flora, is the best characterization. Summary: A: Incorrect - The male reproductive system does not typically have gram-positive rods. B: Incorrect - Acid-fast rods are not part of the normal flora in the male reproductive system. D: Incorrect - The male reproductive system does not typically have gram-positive spore formers.