HESI A2
Chemistry HESI A2 Practice Test Questions
Question 1 of 5
The molar mass of glucose is 180 g/mol. If an IV solution contains 5 g of glucose in 100 g of water, what is the molarity of the solution?
Correct Answer: C
Rationale: To calculate molarity, we need to find the number of moles of solute (glucose) and the volume of the solution. 1. Calculate moles of glucose: 5g / 180 g/mol = 0.0278 mol 2. Calculate total mass of the solution: 5g (glucose) + 100g (water) = 105g 3. Calculate molarity: 0.0278 mol / 0.105 kg = 0.2667 M ≈ 2.8M (Choice C) Rationale: Molarity is moles of solute per liter of solution. The correct answer is C because it correctly calculates the molarity of the solution. Other choices are incorrect as they do not provide the accurate molarity value based on the given information.
Question 2 of 5
Which of these types of intermolecular force is the strongest?
Correct Answer: D
Rationale: Step 1: Define hydrogen bonding as a special type of dipole-dipole interaction. Step 2: Highlight that hydrogen bonding occurs between a hydrogen atom and highly electronegative atom (N, O, or F). Step 3: Emphasize that hydrogen bonding is stronger due to the large electronegativity difference between hydrogen and the other atom. Step 4: Compare the strength of hydrogen bonding to the other types of intermolecular forces. Step 5: Conclude that hydrogen bonding is the strongest intermolecular force due to its specific characteristics and stronger attraction compared to dipole-dipole interaction, London dispersion force, and Keesom interaction.
Question 3 of 5
A salt solution has a molarity of 5 M. How many moles of this salt are present in 0 L of this solution?
Correct Answer: A
Rationale: The correct answer is A: 0 moles. In the given scenario, the volume of the solution is 0 L, which means there is no solution to contain any amount of salt. Molarity is the concentration of a solution in moles of solute per liter of solution. Since the volume is 0 L, there are no moles of salt present. Choice B, C, and D are incorrect because they suggest there are moles of salt present, which is not possible when the volume of the solution is 0 L.
Question 4 of 5
Which ion would you expect to dominate in water solutions of bases?
Correct Answer: D
Rationale: The correct answer is D: OH⁻. In water solutions of bases, OH⁻ ions are dominant as they are responsible for the basic properties. Bases release OH⁻ ions when dissolved in water, leading to an increase in pH. MgCl₂ and 2HCl do not contribute to basicity as they do not release OH⁻ ions. H⁺ ions, found in strong acids, are associated with acidic properties and would not dominate in a base solution.
Question 5 of 5
When an acid is added to a base, water and a salt form. What kinds of bonds form in these two compounds?
Correct Answer: C
Rationale: The correct answer is C: Polar covalent and ionic. When an acid reacts with a base, water and a salt are produced. In water, the bonds between hydrogen and oxygen are polar covalent due to the electronegativity difference between the two atoms. In the salt formed, the bond between the cation and anion is ionic, as one atom donates electrons to the other, resulting in a strong electrostatic attraction. Choice A (Liquid and metallic) is incorrect as it does not describe the bonds formed in water and the salt. Choice B (Polar and nonpolar covalent) is incorrect because nonpolar covalent bonds do not form in this scenario. Choice D (Ionic only) is incorrect because water forms polar covalent bonds, in addition to the ionic bonds in the salt.
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