TEAS Test Sample Math Questions

Correct Answer: B

Rationale: To add 1/6 and 1/2, find a common denominator which is 6. Then, 1/6 + 1/2 = (1/6) + (3/6) = 4/6. Simplifying 4/6 gives 2/3, which is the reduced form of the sum. Choice B is correct. Choices A, C, and D are incorrect because they do not represent the correct result of adding 1/6 and 1/2 in reduced form. Option A simplifies to 9/7, Option C simplifies to 31/36, and Option D simplifies to 3/5, none of which are the correct answer.

Correct Answer: A

Rationale: To round 8.067 to the nearest tenth, we look at the digit in the hundredths place, which is 6. Since 6 is 5 or greater, we round up the digit in the tenths place (0) by 1. Therefore, 8.067 rounded to the nearest tenth is 8.1 (choice B). Choice A, 8.07, is incorrect because we need to round up to 8.1. Choice C, 8, is incorrect because it is rounding down to the nearest whole number. Choice D, 8.11, is incorrect because it is rounding to the nearest hundredth, not the nearest tenth.

Correct Answer: A

Rationale: To express 18/5 as a reduced mixed number, divide 18 by 5. This gives you 3 whole numbers and a remainder of 3. So, the correct answer is 3 3/5. Choice B is incorrect because it doesn't simplify to a whole number and proper fraction. Choices C and D are incorrect as they do not represent the correct division of 18 by 5.

Correct Answer: A

Rationale: To divide fractions, we multiply the first fraction by the reciprocal of the second. So, (4/3) ÷ (9/13) = (4/3) x (13/9) = 52/27. The correct answer is A, 52/27, as it follows the correct procedure of dividing fractions. The other choices are incorrect because they do not result from the proper operation of dividing fractions.

Correct Answer: C

Rationale: The product of two irrational numbers can be either rational or irrational. To understand this, consider √2 * √2 = 2, making it rational. However, √2 * π remains irrational. Therefore, the product can be either rational or irrational, leading to choice C being the correct answer. Choice A is incorrect because the product may be rational. Choice B is incorrect as the product is not always rational. Choice D is incorrect as it does not address the possibility of the product being rational.