ATI TEAS 7
ATI TEAS 7 Version 1 Mathematics Questions
Extract:
Question 1 of 5
A recipe calls for 2.5 teaspoons, which equals approximately 4.93 ml. What is the correct amount of vanilla in ml?
Correct Answer: D
Rationale: To find the correct amount of vanilla in ml, you need to multiply the required teaspoons by the conversion factor. 2.5 teaspoons * 4.93 ml = 12.325 ml. Therefore, the correct amount of vanilla required is 12.325 ml.
Extract:
Question 2 of 5
Which of the following values is the greatest?
Correct Answer: C
Rationale: By comparing these values, it is clear that 4.4 is greater than both 4.25 and the fractions 2/9 and 3/10 Therefore, Option D (4.4) is the greatest value among the options provided.
Question 3 of 5
What is the equivalent weight of 50 kg in pounds (1 kg = 2.2 lb)?
Correct Answer: A
Rationale: To convert 50 kg to pounds, we need to multiply by the conversion factor 2.2 lb/kg. Therefore, 50 kg * 2.2 lb/kg = 110 lb. The correct answer is A, which is 110 lb. The provided conversion factor (1 kg = 2.2 lb) is used to convert kilograms to pounds. By multiplying 50 kg by the conversion factor, we get the equivalent weight in pounds, which is 110 lb.
Question 4 of 5
What is the area of a circle with a diameter of 16 inches in terms of pi (π)?
Correct Answer: B
Rationale: To calculate the area of a circle, you use the formula A = πr^2, where r is the radius of the circle. Since the diameter is given as 16 inches, the radius (r) is half of that, which is 8 inches. By substituting r = 8 into the formula, you calculate the area as A = π(8)� = 64π square inches. Therefore, the correct answer is 64π in squared (Choice B). This calculation is derived from the concept of the radius being half of the diameter in a circle formula.
Question 5 of 5
A farmer grows apple, orange, lemon, banana, and pear trees. The number of trees planted this year is shown in the table above. Which of the following would best display the data?
Correct Answer: A
Rationale: A bar graph is the most appropriate way to display categorical data like the number of each type of tree planted by the farmer. In a bar graph, each type of tree can be represented by a separate bar, allowing for easy visual comparison of the quantities. Scatter plots are used to illustrate relationships between two sets of data, which is not the case here. Stem-and-leaf plots are more suitable for displaying numerical data in a grouped format, not categorical data like types of trees. Line graphs are typically used to portray trends or changes over time, making them less suitable for this scenario.